求导：Iny=(e^y)sin x

x为自变量,y为x的函数.两边对x求导:
y~/y=(e^y)cos(x) +(e^y)sin(x)y~
这里y~就是dy/dx,(e^y)sin(x)y~是e的y次方然后乘以sin x再乘以dy/dx.
把y~合并同类项，得：
y~(1/y-(e^y)sin(x))=(e^y)cos(x)
所以：y~=(e^y)cos(x)/(1/y-(e^y)sin(x))

两边求导得:
y'/y=(e^y)sinx*y'+(e^y)cosx
y'(1/y-(e^y)sinx)=(e^y)cosx
y'=dy/dx=(e^y)/[(1/y)-(e^y)sinx]